Zend Framework Forum - View Single Post - Zend_Input_Filter problems and best practice question

admin · #1 (**permalink**) 10-27-2007, 08:57 AM

Hi,

I'm having some issue with Zend_Filter_Input and wondered if anyone could help me? All I'm trying to do is have a form submitted, filter/validate it and then if it's not valid render the form again with the filtered data populated in the form elements, but I must be doing something stupid which is probably blindingly obvious to everyone except to me! :-)

My action looks like:

Code:

    public function registerAction()
   {
       if ($this->_request->isPost()) {
           $filters = array(
               '*' => array('StringTrim', 'StripTags', new Component_View_Filter_StripSlashes())
           );
           $validators = array(
               'email' => array(
                   'EmailAddress',
                   'allowEmpty' => false
               ),
               'password' => array(
                    array('StringLength', 6),
                   'allowEmpty' => false
               ),
               'confirm_password' => array(
                   'StringEquals',
                   'fields' => array('confirm_password', 'password'),
                   'allowEmpty' => false
               ),
               'username' => array(
                   'Alnum',
                   array('StringLength', 6, 32),
                   'allowEmpty' => false
               )
           );
           $input = new Zend_Filter_Input($filters, $validators, $this->_request->getPost());
           $input->addNamespace('Component_Validate');
           if ($input->isValid()) {
               echo "Form OK<br />\n";
           } else {
               $messages = $input->getMessages();
               $this->view->invalid = $messages;
           }

Zend_Debug::dump($this->_request->getPost());
Zend_Debug::dump($input);
Zend_Debug::dump($input->address2);

           $this->view->post = $input;
       }
       $this->view->countries = $this->_countries;
   }

The above debug output shows me that the form is being submitted OK, and the filters are being applied. But when I try to access the input value with the getter, I just get a null value:

Code:

array(14) {
 ["username"] => string(0) ""
 ["email"] => string(0) ""
 ["password"] => string(0) ""
 ["confirm_password"] => string(0) ""
 ["firstname"] => string(7) "  foo  "
 ["lastname"] => string(15) "bar            "
 ["address1"] => string(21) "<script>ack!</script>"
 ["address2"] => string(0) ""
 ["city"] => string(22) "          it\'s a test"
 ["county"] => string(0) ""
 ["postalcode"] => string(0) ""
 ["country"] => string(2) "GB"
 ["site_contact"] => string(1) "1"
 ["partner_contact"] => string(1) "1"
}

object(Zend_Filter_Input)#56 (13) {
 ["_data:protected"] => array(10) {
   ["firstname"] => string(3) "foo"
   ["lastname"] => string(3) "bar"
   ["address1"] => string(4) "ack!"
   ["address2"] => string(0) ""
   ["city"] => string(11) "it's a test"
   ["county"] => string(0) ""
   ["postalcode"] => string(0) ""
   ["country"] => string(2) "GB"
   ["site_contact"] => string(1) "1"
   ["partner_contact"] => string(1) "1"
 }
 ...
}

NULL

Anyone know why this might be? I've also tried to use $input->getEscaped() but without any luck.

Do the filtered values only get returned if the form is valid?

Also, in my view I have something like this:

Code:

<?php echo $this->formText('address2', $this->post->address2, array('id' => 'frm_address2', 'maxlength' => 48)); ?>

Which produces an empty element on the submit (because of the above issue), and an error prior to form submission because the post view variable doesn't exist yet. Obviously I could wrap the $this->post->address2 in a ternary statement, or something, to default the value, but I wondered what best practise on this was? Remembering that I want to display the filtered values again and not the raw ones that I could with $_POST.

Any help or advice would be truly appreciated!!

Thanks,

Andy

PS: I posted instead of Andy amnuts because he had some problems posting the code.